A+B Format

题目

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
  • 时间限制: 400 ms
  • 内存限制: 64 MB
  • 代码长度限制: 16 KB

Input Specification:

Each input file contains one test case. 
Each case contains a pair of integers a and b where −106 ≤ a,b ≤ 106.
The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line.
The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

我的作答 编译器：C++(g++)

#include <iostream>
using namespace std;

int main()
{
    int a, b, temp[2], i;
    cin >> a >> b;
    int sum = a + b;
    for(i = 0; sum >= 1000 || sum <= -1000; ++i)
    {
        temp[i] = (sum % 1000 < 0) ? (-(sum % 1000)):(sum % 1000);
        sum /= 1000;
    }
    cout << sum;
    for(i -= 1; i >= 0; --i)
    {
        printf(",%03d", temp[i]);
    }
    return 0;
}